一、行转列1.1、初始测试数据表结构:TEST_TB_GRADESql代码:1 create table TEST_TB_GRADE2 (3 ID NUMBER(10) not null,4 USER_NAME VARCHAR2(20 CHAR),5 COURSE VARCHAR2(20 CHAR),6 SCORE FLOAT7 )初始数据如下图:
1.2、 如果需要实现如下的查询效果图:
这就是最常见的行转列,主要原理是利用decode函数、聚集函数(sum),结合group by分组实现的,具体的sql如下:Sql代码:1 select t.user_name,2 sum(decode(t.course, '语文', score,null)) as CHINESE,3 sum(decode(t.course, '数学', score,null)) as MATH,4 sum(decode(t.course, '英语', score,null)) as ENGLISH5 from test_tb_grade t6 group by t.user_name7 order by t.user_name1.3、延伸如果要实现对各门功课的不同分数段进行统计,效果图如下:
具体的实现sql如下:Sql代码:01 select t2.SCORE_GP,02 sum(decode(t2.course, '语文', COUNTNUM,null)) as CHINESE,03 sum(decode(t2.course, '数学', COUNTNUM,null)) as MATH,04 sum(decode(t2.course, '英语', COUNTNUM,null)) as ENGLISH05 from (06 select t.course,07 case when t.score <60 then '00-60'08 when t.score >=60 and t.score <80 then '60-80'09 when t.score >=80 then '80-100' end as SCORE_GP,10 count(t.score) as COUNTNUM11 FROM test_tb_grade t12 group by t.course, 13 case when t.score <60 then '00-60'14 when t.score >=60 and t.score <80 then '60-80'15 when t.score >=80 then '80-100' end16 order by t.course ) t217 group by t2.SCORE_GP18 order by t2.SCORE_GP二、列转行1.1、初始测试数据表结构: TEST_TB_GRADE2 Sql代码: 1 create table TEST_TB_GRADE22 (3 ID NUMBER(10) not null,4 USER_NAME VARCHAR2(20 CHAR),5 CN_SCORE FLOAT,6 MATH_SCORE FLOAT,7 EN_SCORE FLOAT8 )初始数据如下图:
1.2、 如果需要实现如下的查询效果图:
这就是最常见的列转行,主要原理是利用SQL里面的union,具体的sql语句如下:Sql代码: 1 select user_name, 'CN_SCORE' COURSE , CN_SCORE as SCORE from test_tb_grade2 2 union3 select user_name, 'MATH_SCORE' COURSE, MATH_SCORE as SCORE from test_tb_grade2 4 union5 select user_name, 'EN_SCORE' COURSE, EN_SCORE as SCORE from test_tb_grade2 6 order by user_name,COURSE也可以利用【insert all into ... select】来实现,首先需要先建一个表TEST_TB_GRADE3:Sql代码: 1 create table TEST_TB_GRADE3 2 ( 3 USER_NAME VARCHAR2(20 CHAR), 4 COURSE VARCHAR2(20 CHAR), 5 SCORE FLOAT 6 ) 再执行下面的sql: Sql代码: 1 insert all2 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '语文', CN_SCORE)3 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '数学', MATH_SCORE)4 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '英语', EN_SCORE)5 select user_name, CN_SCORE, MATH_SCORE, EN_SCORE from test_tb_grade2;6 commit; 别忘记commit操作,然后再查询TEST_TB_GRADE3,发现表中的数据就是列转成行了。